If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2-322x-336=0
a = 1; b = -322; c = -336;
Δ = b2-4ac
Δ = -3222-4·1·(-336)
Δ = 105028
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{105028}=\sqrt{484*217}=\sqrt{484}*\sqrt{217}=22\sqrt{217}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-322)-22\sqrt{217}}{2*1}=\frac{322-22\sqrt{217}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-322)+22\sqrt{217}}{2*1}=\frac{322+22\sqrt{217}}{2} $
| 15=-5x+40 | | 10+d=-10−4d | | 5x1=14 | | 50x+40=90 | | -3c=-7−4c | | 26=3(x+3)5 | | 2/5y-8=10 | | 6x-3x+4-2x=0 | | 3500÷n=50 | | -8g=-10−9g | | 10q+2=8q+9+q | | -10b+9=-8+7b | | 8n=4= | | 7p+7=-3+8p | | -10−4w=6w | | 1/2-1/3x=1 | | 4x-7=43+x | | -5−8j=5−10j | | 9u+6=u−10+10 | | 10+3b=4b | | 1/2-1/3x=(2/3+1/3)² | | 3d=5d+10 | | t=6+4t=2t+9 | | 11x-2+6x7=90 | | 6(x-4)+x+5=180 | | -4p−4=6−3p | | 2+3f=2f+10 | | 11x-2+6x-7=90 | | -3g=-7g+8 | | 3x+29=5x+9+ | | 2x-1/4x=1 | | -10+9q=7q+8 |